Question

The diameter of a roller is 84cm and it's length is 120cm. It takes 500 complete revolution to move once to level the play ground. Find the area of play ground.

Answer 1

Given: diameter , d= 84cm  and its length , h= 120cm

Since a roller is in cylindrical shape.

Height (h) of cylindrical roller = Length of roller = 120 cm

Radius (r) of the circular end of roller = 

CSA of roller = 2πrh



∴Area of field = 500 × CSA of roller

= (500 × 31680) cm2

= 15840000 cm2

= 1584 m2

Answer 2

QUESTION==$<b>$The diameter of a roller is 84cm and its length is 120cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground



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SOLUTION

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Radius of the roller (r) = 84/ 2 cm = 42 cm 

Length of the roller (h) = 120 cm 

Curved surface area of the roller = 2πrh 

= 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2= 31680 cm2 

∴ area covered by the roller in 1 revolution = 31680 cm2 

∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm

Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2 Ans.