the diameter of a roller is 84cm and its length is 120 cm It takes 500 complete Revolution to move once over the level of playground find the area of playground in metre square
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1
radius 42 and l 120
42
42
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14
Lateral surface area of a roller = 2πrh
= 2×22/7×84/2×120
=31,680 cm
revolution= 500
area of playground= 31680×500
= 15840000 cm^2
= 15840000/100
=158400m^2
= 2×22/7×84/2×120
=31,680 cm
revolution= 500
area of playground= 31680×500
= 15840000 cm^2
= 15840000/100
=158400m^2
sujal5064:
thanks sister
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