Math, asked by BrainlyRacer, 1 year ago

The diameter of a roller of 1.5 m long is 84 cm . If it takes 100 revolution to level a playground , Find the levelling this ground at the rate of 50 paise per square metre.


Answers

Answered by siddhartharao77
17

Answer:

198

Step-by-step explanation:

Given, Length of roller = h = 84 cm = 0.84 m

Given, diameter of roller = 1.5 m.

Then, radius = 0.75 m.

We know that Curved surface area of roller = 2πrh

= 2 * 22/7 * 0.75 * 0.84

= 27.72/7

= 3.96 m²


Thus,

Area of play ground = 100 * CSA of roller

                                 = 100 * 3.96

                                 = 396 m²



Given, cost of leveling per m² = 50 paise = 0.5 rupee.

Cost of leveling 396 m² = 396 * 0.5

                                       = 198


Therefore, Cost of leveling is 198.


Hope it helps!

Answered by Siddharta7
4

Step-by-step explanation:

answer is explained below

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Siddharta7: brainliest it
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