The diameter of a roller of 1.5 m long is 84 cm . If it takes 100 revolution to level a playground , Find the levelling this ground at the rate of 50 paise per square metre.
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Answered by
17
Answer:
198
Step-by-step explanation:
Given, Length of roller = h = 84 cm = 0.84 m
Given, diameter of roller = 1.5 m.
Then, radius = 0.75 m.
We know that Curved surface area of roller = 2πrh
= 2 * 22/7 * 0.75 * 0.84
= 27.72/7
= 3.96 m²
Thus,
Area of play ground = 100 * CSA of roller
= 100 * 3.96
= 396 m²
Given, cost of leveling per m² = 50 paise = 0.5 rupee.
Cost of leveling 396 m² = 396 * 0.5
= 198
Therefore, Cost of leveling is 198.
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