The diameter of a sphere is decreased by 50%. What is the ratio between initial and final curved surface areas?
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1
Answer:
1:4
Step-by-step explanation:
initial CSA = 4 πr²
= 4×π×(d/2)²
diameter decreased 50%
d = 2r
d = 2r - 50/100×2r
d = 2r-r
d =r
new CSA = 4πr²
= 4πd²
ratio = 4πd²/4× 1/4πd²
= 1:4 ans
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