the diameter of circular park is 56m. a 2m wide road runs out side around it . find the amount of cementing the road at 10 rupee sq. m
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d=56m
r=28cm
R=28+ 2
=30m
area of road=π[R^2 - r^2]
=22/7 *(30^2 - 28^2)
=22/7*(30+28)(30-28)
=22/7*58*2
= 364.57sq. m
total cost =364.57*10
=₹3645.7
PLEASE MARK IT AS BRAINLIEST.
r=28cm
R=28+ 2
=30m
area of road=π[R^2 - r^2]
=22/7 *(30^2 - 28^2)
=22/7*(30+28)(30-28)
=22/7*58*2
= 364.57sq. m
total cost =364.57*10
=₹3645.7
PLEASE MARK IT AS BRAINLIEST.
anupam2002:
please mark me as brainliest if it helped u
diameter is 56
and road is built outside it
see my answer
Answered by
6
please mark it as brainliest
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