Question

the diameter of front and rear wheel of the tractor is 80 cm and 2m respectively . find the no. of revolution of the rear wheel will make if it covers the same distance covered by the front wheel in 1400 revolutions.​

Answer 1

Answer:

Given diameter of front wheels(2r)=80cm⇒r=40cm

diameter of rear wheels(2r)=2m⇒r=1m=100cm

In one revolution area covered is =2πr

∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)

Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)

As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)

x=

100

1400×40

=560

That means rear wheel will make 560 revolutions to cover the required distance.

Answer 2

Answer:

Given diameter of front wheels(2r)=80cm⇒r=40cm

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cm

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)x=

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)x= 100

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)x= 1001400×40

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)x= 1001400×40

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)x= 1001400×40 =560

Given diameter of front wheels(2r)=80cm⇒r=40cm diameter of rear wheels(2r)=2m⇒r=1m=100cmIn one revolution area covered is =2πr∴ Distance covered by front wheel in 1400 revolutions =1400×2π(40)Let us assume that to cover same distance rear wheel will take x revolutions=x×2π(100)As both wheel will cover same distance ∴1400×2π(40)=x×2π(100)x= 1001400×40 =560That means rear wheel will make 560 revolutions to cover the required distance