Question

the diameter of the base of a right circular cylinder is 42 cm and its hight is 10 cm.find the curved surface, total surface area and volume? ​

Answer 1

$\large\bf \bullet Given$

The diameter of the base of a right circular cylinder is 42 cm and its hight is 10 cm

$\large\bf\bullet To\;Find$

CSA

TSA

Volume

$\large\bf\bullet Solution$

We know that

Radius = Diameter/2

Radius = 42/2

Radius = 21 cm

Now

~Finding CSA

CSA = 2πrh

CSA = 2 × 22/7 × 21 × 10

CSA = 44/7 × 21 × 10

CSA = 44 × 3 × 10

CSA = 132 × 10

CSA = 1320 cm²

~Finding TSA

TSA = 2πr(r + h)

TSA = 2 × 22/7 × 21(21 + 10)

TSA = 44/7 × 21 (31)

TSA = 44 × 3 × 31

TSA = 4092 cm²

~Finding Volume

Volume = πr²h

Volume = 22/7 × (21)² × 10

Volume = 22/7 × 21 × 21 × 10

Volume = 22 × 3 × 21 × 10

Volume = 13860 cm³

Answer 2

Given:

The diameter of the base of a right circular cylinder is 42 cm and its hight is 10 cm.

To Find:

• Curved surface area,
• Total surface area
• Volume

Solution:

• Diameter of cylinder = 42cm
• Radius = 21cm
• Height = 10cm

CSA of cylinder = 2πrh

➠ CSA of cylinder = 2 × 22/7 × 21 × 10

➠ CSA of cylinder = 2 × 22 × 3 × 10

➠ CSA of cylinder = 1320cm²

TSA of cylinder = 2πr (h + r)

➠ 2 × 22/7 × 21 (10 + 21)

➠ 2 × 22 × 3 × 31

➠ 4092cm²

Volume of cylinder = πr²h

➠ Volume of cylinder = 22/7 × 21 × 21 × 10

➠ Volume of cylinder = 22 × 3 × 21 × 10

➠ Volume of cylinder = 12680cm³