Question

The diameter of the brass rod is 4 mm. Young's modulus of brass is 9.2X10^10
N/m2
a) Calculate in SI units the stress and strain when it is stretched by 0.25% of
its length
b) What is the force exerted?​

Answer 1

Answer:

solved below

Explanation:

E = 9.2X10^10 N/m2

stretched by 0.25% of  its length . strain ∈ =  25 x 10∧-4

a) stress   s = E∈ = 9.2X10^10 N/m2  x 25 x 10∧-4 = 230 x 10∧6 N/m2

s = 230 N/mm²

b) force = 230 x π(16) = 3680πN = 11561 N.

Answer 2

Answer:

11561N

Explanation:

E = 9.2X10^10 N/m2

stretched by 0.25% of  its length . strain ∈ =  25 x 10∧-4

a) stress   s = E∈ = 9.2X10^10 N/m2  x 25 x 10∧-4 = 230 x 10∧6 N/m2

s = 230 N/mm²

b) force = 230 x π(16) = 3680πN = 11561 N.

hope it's helpful to you