Question

The diameter of the circle is 52 cm and the length of one of its chord is 20 cm. Find the distance of the chord from
the center​

Answer 1

Answer:

d=Vr^2-(C/2) 2

= v26 ^2-10^2 =v676-100=v576

= 24cm

distance of the chord from the centre is 24cm

Answer 2

The distance of the chord from the center is 24 cm.

Step-by-step explanation:

Since we have given that

Diameter of circle = 52 cm

So, Radius = $\dfrac{52}{2}=26$

Length of one of its chord = 20 cm

So, distance of the chord from the center would be

$H^2=B^2+P^2\\\\26^2=10^2+P^2\\\\676=100=P^2\\\\676-100=P^2\\\\576=P^2\\\\P=\sqrt{576}\\\\P=24\ cm$

Hence, the distance of the chord from the center is 24 cm.

# learn more:

Diameter of a circle is 26 CM. and length of a chord of the circle is 24 CM. Find the distance of the chord from the center

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