Math, asked by elizaford, 4 months ago

The diameter of the circle
x^2 + y^2 – 6x + 8y – 11 = 0 is

Answers

Answered by janvimittal85

1

Step-by-step explanation:

x^2+y^2-6x+8y-11=0

x+y-6x+8y-11=0

-5x+9y-11=0

-5x+9y=0+11

-5x+9y=11

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