The diameter of the lower and upper ends of a bucket (in the form of a frustum of cone) are 10cm and 30cm respectively.if its height is 24cm, find the area of the metal sheet used to make the bucket
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Diameter of upper end of bucket ,d₁ = 30cm
so, radius of upper end of bucket , r₁ = 15cm
Diameter of lower end of bucket , d₂ = 10cm
so, radius of lower end of bucket , r₂ = 5cm
height of bucket , h = 24cm
lateral length of bucket , L = √(h² + (r₁-r₂)²}
=√{24² + (15-5)²}=√(576+100)=26cm
So, the area of metal sheet require to make it = π(r₁ + r₂)L + πr₁²
= π(15 + 5) × 26 + π(5)²
= π × 20 × 26 + 25π
= 520π + 25π
= 545π
= 545 × 3.14
= 1711.3 cm²
so, radius of upper end of bucket , r₁ = 15cm
Diameter of lower end of bucket , d₂ = 10cm
so, radius of lower end of bucket , r₂ = 5cm
height of bucket , h = 24cm
lateral length of bucket , L = √(h² + (r₁-r₂)²}
=√{24² + (15-5)²}=√(576+100)=26cm
So, the area of metal sheet require to make it = π(r₁ + r₂)L + πr₁²
= π(15 + 5) × 26 + π(5)²
= π × 20 × 26 + 25π
= 520π + 25π
= 545π
= 545 × 3.14
= 1711.3 cm²
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