Question

The diameter of the spehere is decreased by 25% find is new volume ​

Answer 1

Answer:

57.81% decrease found in new volume

Step-by-step explanation:

Let the original diameter is D,and radius is r.

New diameter is D' and radius r'.

since the D' =3D/4

radius r'=3r/4

Volume of sphere

$V = \frac{4}{3} \pi {r}^{3}$

Volume of new sphere

$V'= \frac{4}{3} \pi {(r')}^{3} \\ \\ = \frac{4}{3} \pi {( \frac{3r}{4} )}^{3} \\ \\ V'= ( \frac{27}{64}) \frac{4}{3} \pi {r}^{3}$

So,the ratio of new volume to older volume is 64:27.

% decrease in new volume

$= \frac{ \frac{4}{3} \pi {r}^{3} -( \frac{27}{64} )\frac{4}{3} \pi {r}^{3} }{\frac{4}{3} \pi {r}^{3}} \times 100 \\ \\ = \frac{1 - \frac{27}{64} }{1} \times 100 \\ \\ = \frac{64 - 27}{64} \times 100 \\ \\ = \frac{37}{64} \times 100 \\ \\ = \frac{3700}{64} \\ \\ = 57.81$

Hope it helps you.

Answer 2

Answer:

57.81

Is ur answer Yaar

I hope it will help you yaar

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