the diameter of two discs are in the ratio of 2:3 what will be the ratio of their areas and how?
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ankita200683:
thnx but sry this is the wrong ans the correct answer is 4:9
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LET THE SIDES BE X
SO DIAMETER OF FIRST CICLE =2X
CSA=2πRH
2π(2X/2)h...........eq 1
the diameter of 2nd circle =3x
CSA=2π(3x/2)h............eq 2
ratio of their areas= (2π(2x/2)h) / (2π(3x/2)h
answer= 2:3
HOPE IT WILL HELP YOU ALL
THANKS...............
SO DIAMETER OF FIRST CICLE =2X
CSA=2πRH
2π(2X/2)h...........eq 1
the diameter of 2nd circle =3x
CSA=2π(3x/2)h............eq 2
ratio of their areas= (2π(2x/2)h) / (2π(3x/2)h
answer= 2:3
HOPE IT WILL HELP YOU ALL
THANKS...............
sry but the answer is 4:9in my book
apne q galat diya h isme area nhi volume ka rato pucha hoga kyonki area ka ratio to yahi hoga...........thnx
nahi area ka ratio diya h and avi mera ans nikal gaya. The ans is 4:9
send pic of that solution
plz
ask question
venkatesh5046 yours and my ans are same
can you say for which question
the dia. of tow disc wala questions
but how will I send the pic of solution?
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