the diameter of two discs are in the ratio of 2:3 what will be the ratio of their areas and how?
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think this will help you
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ankita200683:
thnx but sry this is the wrong ans the correct answer is 4:9
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LET THE SIDES BE X
SO DIAMETER OF FIRST CICLE =2X
CSA=2πRH
2π(2X/2)h...........eq 1
the diameter of 2nd circle =3x
CSA=2π(3x/2)h............eq 2
ratio of their areas= (2π(2x/2)h) / (2π(3x/2)h
answer= 2:3
HOPE IT WILL HELP YOU ALL
THANKS...............
SO DIAMETER OF FIRST CICLE =2X
CSA=2πRH
2π(2X/2)h...........eq 1
the diameter of 2nd circle =3x
CSA=2π(3x/2)h............eq 2
ratio of their areas= (2π(2x/2)h) / (2π(3x/2)h
answer= 2:3
HOPE IT WILL HELP YOU ALL
THANKS...............
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