the diameter of zinc atom is 2.6 Armstrong find the no of atom present in 1.6cm length is
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given,
diameter of carbon atom =2.6 A
radius of carbon atom =[2.6/2] =1.3A
length of line =1.6cm
number of carbon atoms which can be place along the line is given by n =[ 1.6×10^-2] /[ 2.6×10^-10]
n= 61.538×10^6
therefore, the number of carbon atom which can be place along the line is 61.538×10^6
diameter of carbon atom =2.6 A
radius of carbon atom =[2.6/2] =1.3A
length of line =1.6cm
number of carbon atoms which can be place along the line is given by n =[ 1.6×10^-2] /[ 2.6×10^-10]
n= 61.538×10^6
therefore, the number of carbon atom which can be place along the line is 61.538×10^6
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