The diameters is lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm and height is 24 cm. Find the capacity of the bucket
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Answer: 8171.428 cm^3
Step-by-step explanation:
Here,
h = 24
R = 5
r = 15
Volume of Frustum = 1/3 x π x (R^2 + r^2 + Rr) x h
=> 1/3 x 22/7 x [25 + 225 + 75] x 24
=> 8 x 22/7 x [325] = 8171.428 cm^3
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