Question

The diameters of three circles are in the ratio 3 : 5 : 6. If the sum of the circumferences of these circles be 308 cm; find the difference between the areas of the largest and the smallest of these circles.​

Answer 1

Step-by-step explanation:

Let the diameters be- 3x,5x,6x

therefore radius=3x/2,5x/2,6x/2

sum of circumferences is- 308

Let circumference of 1st circle be-A

circumference of 2nd circle be- B

circumference of 3rd circle be- C

A=2×22/7×3x/2

A=132x/14

B=2×22/7×5x

B=220x/14

C=2×22/7×6x/2

C=264x/14

A+B+C=308

132x/14+220x/14+264x/14=308

616x/14=308

616x=308×14

616x=4312

x=616/4312

x=7

You can do the rest

Answer 2

the correct answer is given above is the right answer