The diameters PQ and RS of the circle with centre C are perpendicular to each other at C. State, why arc PS and arc SQ are congruent. Write the other arcs which are congruent to arc PS
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Answered by
61
Hi ,
It is given that ,
Diameters PQ and RS of the circle with center
C are perpendicular to each other at C.
Join P , Q to R and S shown in the picture.
Now ,
In ∆PCS , ∆QCS
CP = CQ ( radius )
CS = CS ( common side )
<PCS = <QCS = 90°
Therefore ,
∆PCS congruent to ∆QCS
( side , angle , side congruency )
PS = SQ [ corresponding parts of congruent
triangles ]
arc PS congruent arc SQ
[ If the angles subtended by two chords
at the center are equal , then the chords
are congruent. ]
And
arc PQ = arc SQ = arc QR = arc RP
all arc arc congruent to each other.
I hope this helps you.
: )
It is given that ,
Diameters PQ and RS of the circle with center
C are perpendicular to each other at C.
Join P , Q to R and S shown in the picture.
Now ,
In ∆PCS , ∆QCS
CP = CQ ( radius )
CS = CS ( common side )
<PCS = <QCS = 90°
Therefore ,
∆PCS congruent to ∆QCS
( side , angle , side congruency )
PS = SQ [ corresponding parts of congruent
triangles ]
arc PS congruent arc SQ
[ If the angles subtended by two chords
at the center are equal , then the chords
are congruent. ]
And
arc PQ = arc SQ = arc QR = arc RP
all arc arc congruent to each other.
I hope this helps you.
: )
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