C is the centre of the circle whose radius is 10 cm. Find the distance of the chord from the centre if the length of the chord is 12 cm.
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Given ,
C is the centre of the circle.
radius ( AC ) = 10 cm
Chord ( AB ) = 12 cm
draw CM perpendicular to AB.
CM bisects AB .
AM = AB/2
AM = 12/2 = 6 cm
i ) In ∆ACB ,
<AMC = 90°
By Phythogarian theorem ,
AM² + CM² = AC²
6² + CM² = 10²
CM² = 100 - 36
CM = √64
CM = 8 cm
Therefore ,
Distance from the chord to centre
= CM = 8 cm
••••
C is the centre of the circle.
radius ( AC ) = 10 cm
Chord ( AB ) = 12 cm
draw CM perpendicular to AB.
CM bisects AB .
AM = AB/2
AM = 12/2 = 6 cm
i ) In ∆ACB ,
<AMC = 90°
By Phythogarian theorem ,
AM² + CM² = AC²
6² + CM² = 10²
CM² = 100 - 36
CM = √64
CM = 8 cm
Therefore ,
Distance from the chord to centre
= CM = 8 cm
••••
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