Question

The die is thrown once. What is the probability of getting (i) A 22. In a non leap year, find the probability of getting 53 Mondays. (ii) D. (CBSE 2006) 23. What is probability that a leap year has (CBSE 2015)​

Answer 1

The die is thrown once. What is the probability of getting

• Required Probability P(E) = 2/6 = 1/3.

In a non leap year, find the probability of getting 53 Mondays.

• 0.14 or 1/7 is probability for 53 Mondays in a non-leap year

What is probability that a leap year has Sunday ?

• There are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is72.

Answer 2

${\huge{\boxed{\mathcal{\red{Answer}}}}} \leqslant$

A) For non leap year there are 365 days in a year.

365 days =52 weeks and 1 day.

that remaining 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday.

so total numer of outcomes =7

favorable outcome is Monday to have 53 Mondays in that year.

so total number of favorable outcome=1

Hence p(getting 53 Mondays in a non-leap year)=1/7

B) For leap year there are 366 days in a year.

366 days =52 weeks and 2 days.

that remaining 2 days can be (Sunday, Monday);(Monday,Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday),(Friday, Saturday), (Saturday, Sunday)

so total numer of outcomes =7

favorable outcomes are (Thursday, Friday),(Friday, Saturday) to have 53 Fridays in that year.

so total number of favorable outcome=2

Hence p(getting 53 Fridays in a

leap year)=2/7

C) For leap year there are 366 days in a year.

366 days =52 weeks and 2 days.

So it is a certain event to get 52 Sundays in a leap year.

Hence p(getting 52 Sundays in a leap year) = 1