the dielectric constant of water is 80.what is its permitivity?
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The permittivity of free space (a vacuum)is a physical constant equal to approximately8.85 x10−1210−12 farad per meter (F/m).By definition,
permittivity of water = dielectric constant x permittivity of vacuum
Therefore,
permittivity of water = 80.10 x 8.85 x10–1210–12 = 7.08885 x 10–1010–10 farad/metre
permittivity of water = dielectric constant x permittivity of vacuum
Therefore,
permittivity of water = 80.10 x 8.85 x10–1210–12 = 7.08885 x 10–1010–10 farad/metre
dk21giri:
make it easy its only a 1 mark question
you can write this line permittivity of water = 80.10 x 8.85 x10–1210–12 = 7.08885 x 10–1010–10 farad/metre
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