Question

The difference b/w the ages of two cousins is 10 years. 15 years ago if the elder one was twice
as old as the younger one Find their present age.​

Answer 1

Answer:

15 years ago, if the elder one was twice as old as the younger one, find their present ages. Solution. 10 + − 15 = 2( − 15) → = 25 → = 35 Answer. Cousins present ages are 25 and 35 years.

Step-by-step explanation:

Let the present age be x then 2nd's age= x+10

15 years ago'

(x-15)*2=(x+10-15)

2x-30=x-5

2x-x=30-5

x=25 years

x+10=35 years