Math, asked by somani1995patro, 1 year ago

the difference between a discount of 40% on rs.500 and two successive discounts of 36% and 4% on the same amount is?

Answers

Answered by Shreyasahoo
20

Answer:

The difference is Rs. 7.2.

Step-by-step explanation:

First Case:

Rs.500-40% of 500

=Rs.500-40/100×500

=Rs.500-200

=Rs.300

Second Case:

1)Rs.500-36%of 500

=Rs.500-36/100×500

=Rs.500-180

=Rs.320

2) Rs. 320-4% of 320

=Rs.320-4/100×320

= Rs. 320-12.8

=Rs. 307.2

THEREFORE,

Rs. 307.2-Rs.300=Rs.7.2

Answered by payalchatterje
2

Answer:

Required difference is Rs7.20.

Step-by-step explanation:

Marked price is Rs. 500

Discount = Rs. 40%

Selling Price = Marked Price − Discount

=500 -  \frac{40}{100}  \times 500 = Rs300.....(1)

Marked Price is Rs. 500.

Successive discount of 36% and 4%

Selling price after 36% discount

=500 -  \frac{36}{100}  \times 500 =Rs 320

Selling Price after 4% discount

=320 -  \frac{4}{100}  \times 320 = Rs307.20 ......(2)

Subtract (2) − (1), we get

= Rs. (307.20−300)

= Rs. 7.20

Difference between two types of discount is Rs 7.20.

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