Question

The difference between a three digit number and a number formed by reversing its digits is 198. Determine the number, if the sum of the digits is 5.

Answer 1

The let no be 100y + 10z + v
When reversed it becomes 100v +10z +y
y + z + v = 5
100y + 10z +v - 100v - 10z - y = 198
99(y - v) = 198
y - v = 2

In order the sum to be 5 the digits must be combinatio of 1,2, 0,3
y - v = 2 this happens when y is 3 and v is 1
y + v = 3+1 = 4
y +v +z = 4 + z = 5
z = 1
So the no would be 311 and 113
311 - 113 = 198
U may also think that y - v = 2 when y is 2 and v is 0
So z would be 3
So the number formed would be 230
But on reversing it becomes 032,which is not a three digit
So the numbers 311 and 113

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