the difference between a two digit number and the number obtained by reversing the digits is 36 and the digit at tens place is double the digit at ones place.find the original number
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let the original number be 10x+y
10x+y-(10y+x)=36
10x+y-10y-x=36
9x-9y=36
x-y=4
x=4+y
x=2y
2y=4+y
y=4
x=2y
x=8
the number is 10x+y
=84
10x+y-(10y+x)=36
10x+y-10y-x=36
9x-9y=36
x-y=4
x=4+y
x=2y
2y=4+y
y=4
x=2y
x=8
the number is 10x+y
=84
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