The difference between c.i and S.I on a certain sum of money at 10%p.a for 2 years is rs 750 .find the sum if interest is compound annually
Answers
Answered by
0
let the sum be x
means principal be x
then in si = p*r*t/100
= x*10*2/100 solve it then after that
another column ci
=x(1+r/100)2 as a power
then sole it whatever the si and ci comes
solve this = ci-si=750
your answer comes
means principal be x
then in si = p*r*t/100
= x*10*2/100 solve it then after that
another column ci
=x(1+r/100)2 as a power
then sole it whatever the si and ci comes
solve this = ci-si=750
your answer comes
Answered by
2
Heya friend,
Given that
R = 10% P.a.
T = 2 years
Difference = ₹750
Solution
Let the sum be ₹P. Then,
S.I. = P×R×T/100
= P×10×2/100
= ₹P/5
C.I. = P{(1+R/100)^n - 1}
= P{(1+10/100)^2 - 1}
= P{(100+10/100)^2 - 1}
= P{(110/100)^2 - 1}
= P{(11/10)^2 - 1}
= P{121/100 - 1}
= P{121-100/100}
= ₹21 P/100
Difference = C.I. - S.I.
=> 750 = 21 P/100 - P/5
=> 750 = 21 P - 20 P/100
=> 750 = P/100
=> P = 100 × 750
=> P = ₹75,000
Hence, the sum is ₹75,000.
Thanks
With regards@
Tanisha
Given that
R = 10% P.a.
T = 2 years
Difference = ₹750
Solution
Let the sum be ₹P. Then,
S.I. = P×R×T/100
= P×10×2/100
= ₹P/5
C.I. = P{(1+R/100)^n - 1}
= P{(1+10/100)^2 - 1}
= P{(100+10/100)^2 - 1}
= P{(110/100)^2 - 1}
= P{(11/10)^2 - 1}
= P{121/100 - 1}
= P{121-100/100}
= ₹21 P/100
Difference = C.I. - S.I.
=> 750 = 21 P/100 - P/5
=> 750 = 21 P - 20 P/100
=> 750 = P/100
=> P = 100 × 750
=> P = ₹75,000
Hence, the sum is ₹75,000.
Thanks
With regards@
Tanisha
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