Question

The difference between nth and (n+1) th Bohr orbits' radii of H atom is equal to its (n- 1) th Bohr orbit's radius. The value of n is:-

Answer 1

Answer:

The value of n is 4.

Explanation:

$r_n=\frac{n^2\times 52.9}{Z}$   (in pm)

where,

$r_n$ = radius of $n^{th}$ orbit

n = number of orbit

Z = atomic number of hydrogen = 1

$r_n-r_{n+1}=r_{n-1}$

$\frac{(n+1)^2\times 52.9}{Z}-(\frac{(n)^2\times 52.9}{Z})=\frac{(n-1)^2\times 52.9}{Z}$

$(n+1)^2-(n)^2=(n-1)^2$

n = 4

The value of n is 4.