A's increase is 10% less than that of B. by what per cent is B's income more the A's ?
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let B income be X
A's income= 90℅ of X
B's income is more than A by= X -90℅ofX
= 10℅ of X
so ℅ = (10℅ of X)/ 90% of X . 100
= 100/9 = 11.1%
A's income= 90℅ of X
B's income is more than A by= X -90℅ofX
= 10℅ of X
so ℅ = (10℅ of X)/ 90% of X . 100
= 100/9 = 11.1%
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