the difference between outside and inside curved surface area of a cylindrical metallic pipe 28 cm long is 88 centimetre square if the pipe is made of 198 centimetre cube of metal find the thickness of the pipe
dainvincible1:
see inbox bro
Answers
Answered by
1
Solution:-
Let the outer radius and the inner radius of the cylindrical metallic pipe be 'R' and 'r' respectively.
The height of the pipe = 28 cm (Given)
The difference between the outer and inner curved surface area is 88 cm² (Given)
Therefore,
⇒ 2*πRh = 2*πrh = 88 cm²
⇒ 2*22/7*R*28 - 2*22/7*r*28 = 88
⇒ 2*22/7*28(R - r) = 88
⇒ 1232/7(R - r) = 88
⇒ 176(R - r) = 88
⇒ (R - r) = 88/176
⇒ R - r = 1/2
Or, R - r = 0.5 cm
So, the thickness of the metallic pipe is 0.5 cm.
Answer
Let the outer radius and the inner radius of the cylindrical metallic pipe be 'R' and 'r' respectively.
The height of the pipe = 28 cm (Given)
The difference between the outer and inner curved surface area is 88 cm² (Given)
Therefore,
⇒ 2*πRh = 2*πrh = 88 cm²
⇒ 2*22/7*R*28 - 2*22/7*r*28 = 88
⇒ 2*22/7*28(R - r) = 88
⇒ 1232/7(R - r) = 88
⇒ 176(R - r) = 88
⇒ (R - r) = 88/176
⇒ R - r = 1/2
Or, R - r = 0.5 cm
So, the thickness of the metallic pipe is 0.5 cm.
Answer
Answered by
2
Step-by-step explanation:
Hope it's helpful mate☺
Attachments:
Similar questions