The difference between outside and inside surface areas of cylindrical metallic pipe 14
cm long is 44 m². If the pipe is made of 99 cm³ of metal, find the outer and inner radii of
the pipe.
Answers
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Answer:
given: L = 14 cm, CSA1 - CSA2 = 44cm², Volume of metal V = 99cm³
to find R and r
Step-by-step explanation:
formula used: CSA1 - CSA2 = 2πh( R - r)
=> 2×22/7×14(R - r) = 44
=> R - r = (44×7) / 2×22×14
=> R - r = 1/2........1
V = πh(R² - r²)
99 = 22/7 × 14 ( R² - r²)
=> R² - r² = (99×7) / 22 × 14
=> R² - r² = 9×7/2×14 => 9/4......... 2
R² - r² = (R + r)(R - r)
9/4 = (R+r)(1/2) [ from 1 ]
=> R + r = 9/4 × 2/1
=> R + r = 9/2.......3
solving equations 1 and 3,
=> R - r = 1/2
=> R + r = 9/2
=> 2R = 5
=> R = 2.5 cm
=> 5/2 - r = 1/2
=> r = 5/2 - 1/2 = 2 cm
R = 2.5 cm and r = 2 cm
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