the difference between squares of 2 numbers is 120. The square of smallest number is twice the greater number. Find the number.
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x^2-y^2=120
x^2-2x=120(y^2=2x)
x^2-2x-120=0
(x+10x)(x-12x)=0
x=12
y=√(2*12)=2√6
x^2-2x=120(y^2=2x)
x^2-2x-120=0
(x+10x)(x-12x)=0
x=12
y=√(2*12)=2√6
adarshaj:
Thx
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