Math, asked by atulkumarsinghavi, 5 months ago

The difference between the ages of a father and his son is 24 years currently. Five Years ago the sons age was one third of the fathers age. find their present ages​

Answers

Answered by manjuoxiinc2019
1

Let the ages of father and son be F,S respectively

Given that

⇒F−S=24

⇒F=S+24 ..(1)

3

1

(F−5)=S−5

⇒F−5=3S−15

⇒S+24−5=3S−15

⇒2S=34

⇒S=17

⇒F=S+24=17+24=41

⇒S=17;F=41

Answered by av1266108
2

answer

Given that

⇒F−S=24

⇒F=S+24 ..

 \frac{1}{3} (f - 5) = s - 5

⇒F−5=3S−15

⇒S+24−5=3S−15

⇒2S=34

⇒S=17

⇒F=S+24=17+24=41

⇒S=17;F=41

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