the difference between the ages of two cousins is 10 years. 15 years ago, if the elder. one was twice as old as the younger one, find their present ages
Answers
Answered by
8
a-b=10
a-15=2(b-15)
a-15=2b-30
a-2b= -15
a-b=10
solve them
-b=-25
b=25
a-b=10
a-25=10
a=10+25
a=35
a=35,b=25 is answer
a-15=2(b-15)
a-15=2b-30
a-2b= -15
a-b=10
solve them
-b=-25
b=25
a-b=10
a-25=10
a=10+25
a=35
a=35,b=25 is answer
Answered by
17
difference:- 10 years
suchthat:- 10 and 20
after 15 years:- (10+15) and (20+15)
:- 25 and 35
therefore:- their present ages are 25 and 35
suchthat:- 10 and 20
after 15 years:- (10+15) and (20+15)
:- 25 and 35
therefore:- their present ages are 25 and 35
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