Question

the difference between the ages of two cousins is 10 years 15 years ago if the elder one was twice as old as the younger one find their present age

Answer 1

let the age of elder bro be 'x'
let the age of smaller bro be 'x-10'
As they r talking about 15 years ago so,
x-15 and x -10-15=x-25
Right now the elder brother's age is two times
therefore
x-15=2( x-25)
x-15=2x-50
x=35
elder bro is 35 years old
smaller is 25 years old

Answer 2

at present

age of older one = x

age of younger= x-10

15 years ago their ages

older one = x-15

younger =x-10-15= x-25

age of elder = 2× younger

x-15 = 2 (x-25)

x-15= 2x -50

-15+50=2x-x

35 =x

x=35

therefore

now elder age = x =35yr

younger age = x-10

=35-10 =25