Question

The difference between the ages of two cousins is 12 years. 4 years ago, the age of elder one was four times times the age of younger one. find their present ages​

Answer 1

The "present age" of younger 25.

The "present age" of elder is 35.

Given:

Age difference between two cousins is 10 years.

Elder one is twice older than younger one, 15 years ago.

To find:

To identify the present age of younger and elder cousin.

Solution:

Let y be the "age of the younger cousin".

The age of the elder cousin = y + 10

From the condition which is 15 years ago,

The age of younger cousin, 15 years ago = y - 15

The age of elder cousin, 15 years ago = y + 10 - 15 = y - 5

Again from the condition, we get

y-5=2(y-15)y−5=2(y−15)

y-5=2y-30y−5=2y−30

2y-y=30-52y−y=30−5

y=25y=25

Thus,

Age \ of \ elder \ cousin = y + 10 = 25 + 10 = 35Age of elder cousin=y+10=25+10=35

Answer 2

Answer:

elder cousin : 20; younger cousin: 8

Step-by-step explanation:

Let the present age of the younger one be 'x' and the elder one be 'x+12'

four years ago means:

younger one: x-4

older one: x+12-4

given that: the elder one was four times the age of the younger one,

so,

younger one's age x 4 = older one's age.

so,

4(x-4) = x+12-4

4x-16 = x+8

4x-x = 8+16

3x = 24

x = 24/3

x=8

now,

substituting the value of x in their present ages,

younger one's age is x

so, x=8

=8

older one's age is x+12

= x+12

=8+12

=20