the difference between the circumference and radius of the circle is 37 find the area of a circle
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Answered by
4
Let the radius be r.
Then circumference of the circle = 2πr.
Given; 2πr-r = 37
r( 2π -1 ) = 37
r = 37(2π-1)
2π- 1 = 2(22/7)-1 = 44/7-1 = 37/7
Now r = 37(37/7) = 7 units.
Area of circle =πr² = 22/7*7*7 = 22*7=154 sq.units .
Then circumference of the circle = 2πr.
Given; 2πr-r = 37
r( 2π -1 ) = 37
r = 37(2π-1)
2π- 1 = 2(22/7)-1 = 44/7-1 = 37/7
Now r = 37(37/7) = 7 units.
Area of circle =πr² = 22/7*7*7 = 22*7=154 sq.units .
Answered by
17
❤Here is your solution ❤
Circumference of the circle = 2 × π× r
Let
r = radius
Now,
Given difference of circumference and radius = 37m
A/q
Circumference - r = 37
=>2 π r - r = 37
=>r (2π - 1 )=37
=>r (2×22/7 -1)=37
=>44/7 r -r = 37
=>37r/7= 37
=>r = 7m
Hence
Area of circle = π r ^2 = 3.14 × 7 × 7 = 154 sq. m.
Hope it helps you
Circumference of the circle = 2 × π× r
Let
r = radius
Now,
Given difference of circumference and radius = 37m
A/q
Circumference - r = 37
=>2 π r - r = 37
=>r (2π - 1 )=37
=>r (2×22/7 -1)=37
=>44/7 r -r = 37
=>37r/7= 37
=>r = 7m
Hence
Area of circle = π r ^2 = 3.14 × 7 × 7 = 154 sq. m.
Hope it helps you
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