the difference between the compound interest and simple interest on a certain sum at 10% for 3 years is 93. Find the sum
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Heya friend,
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Let ₹P be the principal. Then,
S.I. = P×R×T/100
= P×10×3/100
= ₹3P/10
C.I. = P{(1+R/100)^n - 1}
= P{(1+10/100)^3 - 1
= P{(100+10/100)^3 - 1}
= P{(110/100)^3 - 1}
= P{(11/10)^3 - 1
= P{1,331/1,000 - 1}
= P{1,331 - 1,000/1,000}
= P{331/1,000}
= ₹331P/1,000
According to question,
C.I. - S.I. = 93
=> 331P/1,000 - 3P/10 = 93
=> 331P - 300P/1,000 = 93
=> 31P/1,000 = 93
=> P = 93×1,000/31
=> P = ₹3,000
Hence, the sum is ₹3,000.
Thanks
With regards@
Tanisha
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Let ₹P be the principal. Then,
S.I. = P×R×T/100
= P×10×3/100
= ₹3P/10
C.I. = P{(1+R/100)^n - 1}
= P{(1+10/100)^3 - 1
= P{(100+10/100)^3 - 1}
= P{(110/100)^3 - 1}
= P{(11/10)^3 - 1
= P{1,331/1,000 - 1}
= P{1,331 - 1,000/1,000}
= P{331/1,000}
= ₹331P/1,000
According to question,
C.I. - S.I. = 93
=> 331P/1,000 - 3P/10 = 93
=> 331P - 300P/1,000 = 93
=> 31P/1,000 = 93
=> P = 93×1,000/31
=> P = ₹3,000
Hence, the sum is ₹3,000.
Thanks
With regards@
Tanisha
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