the difference between the compound interest and the simple interest on a certain sum for 2 years at 5% per annum is rs60. find the sum
Answers
Answered by
22
IN THE FIRST YEAR
P = Rupees 60
R = 5% / annum
T = 1 years
SI = P×R×T/100
= Rs. ( 60 × 5 × 1 / 100)
= Rs. ( 300/100)
= Rs. 3
Now, Amount = P + SI
Amount = Rs. ( 60+3)
Amount = Rs. 63
IN THE SECOND YEAR
P= Rs. 63
R= 5%
T= 1 year
SI = P×R×T/100
= Rs. ( 63 × 5 × 1 / 100)
= Rs. 315/100
= Rs. 3.15
Now, Compound Interest = P + Si
= Rs. 66.15 ( ans )
P = Rupees 60
R = 5% / annum
T = 1 years
SI = P×R×T/100
= Rs. ( 60 × 5 × 1 / 100)
= Rs. ( 300/100)
= Rs. 3
Now, Amount = P + SI
Amount = Rs. ( 60+3)
Amount = Rs. 63
IN THE SECOND YEAR
P= Rs. 63
R= 5%
T= 1 year
SI = P×R×T/100
= Rs. ( 63 × 5 × 1 / 100)
= Rs. 315/100
= Rs. 3.15
Now, Compound Interest = P + Si
= Rs. 66.15 ( ans )
anirban69:
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Answered by
3
let the sum be P = Rs. 100.
time T = 2 years, rate of interest R = 6% per annum
simple interest = PRT/100= 100*6*2/100=
Rs 12
compound amount= P( 1+R/ 100)^T
= 100*(1+6/100) ^2
= 112.36
therefore the compound interest = compound amount - principal
=112.36-100=12.36/-
the difference between the compound interest and simple interest = 12.36-12.00 = 0.36/-
if the difference between the CI and SI is Rs. 0.36 the principal = Rs. 100
if the difference between the CI and SI is Rs. 90 the principal = 100/0.36*90
= 25000
thus the sum is Rs. 25000.
hope this helps you.
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