Math, asked by rituVaryani, 1 year ago

the difference between the length of a side of a right triangle which form the right angle is 3 cm if it's perimeter is 36cm find the lengths of the sides

Answers

Answered by Anonymous
56

HEY THERE!!





Method of Solution!




Suppose the actual length of right Angled Triangle which form the right angle 'x'.




Now, According to the Question Statement!



Other side of right angled triangle = (x+3)




Also, Using Pythagoras theorem!




h²=P²+b²



Here, Before using Pythagoras theorem find the lengths side(Hypotenuse) of right angled triangle!




Measure of hypotenuse Side!



36-x-(x+3)



= 36-x-x-3



= 36-2x-3



=36-3-2x



=33-2x




Now, Using Pythagoras theorem!



here, Base = (x+3), Perpendicular = (x) and Hypotenuse (33-2x)



Substitute the Given value in Equation Formula!




h²=p²+b²



(33-2x)² = (x+3)²+(x)²



1089+4x²-2.2x.33 = x²+9+2.3.x+x²



4x²-132x+1089=x²+9+6x+x²



4x²-132x+1089=2x²+6x+9



4x²-2x²-132x-6x+1089-9=0



2x²-138x+1080 = 0



2(x²-69x+540) = 0



So, x²-69x+540= 0





Solving the Quadratic Equation!




x²-69x+540 = 0



x²-60x-9x+540=0



x(x-60)-9(x-60)=0




(x-60)(x-9)=0



x=60 or 9




Now, According to the Question statement!




Length of sides = 9, 12,15



Also, Length of sides = 60,63,-87.




Thanks!



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Answered by SmãrtyMohït
66

Here is your solutions


Let

length of right Angled Triangle which form the right angle x

A/q


Other side of right angled triangle = (x+3)


Now

To find the lengths side(Hypotenuse) of right angled triangle:-


hypotenuse = 36-x-(x+3)

= 36-x-x-3

= 36-2x-3

=36-3-2x

=33-2x


Hence ,

We have


Base = (x+3)

Perpendicular = (x)

Hypotenuse (33-2x)


Putting Given value in formula :-


Using Pythagoras theorem

 

 h²=p²+b²

(33-2x)² = (x+3)²+(x)²


=>1089+4x²-2.2x.33 = x²+9+2.3.x+x²


=>4x²-132x+1089=x²+9+6x+x²


=>4x²-132x+1089=2x²+6x+9


=>4x²-2x²-132x-6x+1089-9=0


=>2x²-138x+1080 = 0


=>2(x²-69x+540) = 0


=>x²-69x+540= 0


=>x²-69x+540 = 0


=>x²-60x-9x+540=0


=>x(x-60)-9(x-60)=0


=>(x-60)(x-9)=0


=>x = 60 or 9



when  x = 9


Base = (x+3) = 9 +3 =12✔

Perpendicular = (x) = 9✔

Hypotenuse (33-2x) = 33 -2×9 = 15✔


side of triangle =12 9 33



when x = 60



Base = (x+3) = 9 +3 =63✔

Perpendicular = (x) = 60✔

Hypotenuse (33-2x) = -87 ✔


side of triangle 60, 63, -87


Hope it helps you


SmãrtyMohït: thanks
MAYAKASHYAP5101: fab answer✌️
SmãrtyMohït: thanks
Anonymous: amazingly wow ✌
SmãrtyMohït: thanks
Anonymous: Awesome answer.....!
SmãrtyMohït: thanks
Anonymous: osm yarr
SmãrtyMohït: thanks
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