Math, asked by viresh010107, 2 months ago

The difference between the number at unit's place and ten's place is 1. the sum of the numbers by interchanging the numbers in two digit number is 99, then find the number

Subject :- 9th maths

Answers

Answered by ajaydubey1902
1

Step-by-step explanation:

Let the digit at unit place be x.

Then , T. O

x+1. x

Original no.= (x+1)10 + x

10x +10+ x = 11x +10

On reversing digits,,

T. O

x. x+1

No. after interchanging digits,

= x*10 + (x+1)

10x +x+1

=11x + 1

Now, according to question:

11x +1 + 11x + 10=99

= 22x+ 11=99

= 22x = 99-11 = 88

= x = 88/22 = 4

So, original number is:

T. O

4+1. 4

5. 4. = 54

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