Question

The difference between the present ages of a father and his son is 30years.Five years ago,the son's age was one -seventh of the father's age.Find the age of each


What is the present age of father and his son​

Answer 1

Answer:

Sons age is 10 years and father's age is 40 years.

Step-by-step explanation:

let fathers age= x

    sons age=y

x-y=30          - 1

(y-5)=(x-5)/7  -2

substitue value of x in eq. 2.

x=30+y

2 becomes: y-5=(25+y)/7

7y-35 = 25+y

6y=60

y=10

x=30+10=40

Answer 2

Answer:

Present age of -

• father = 40 years
• son = 10 years

Explanation

Let the age of father be M years and age of son be N years.

The difference between the present ages of a father and his son is 30 years.

As per given condition,

Father age (bigger one) - Son age (smaller one) = 30 years

→ M - N = 30

→ M = 30 + N ..........(1)

Five years ago, the son's age was one-seventh of the father's age.

Five years ago:

• Age of father = (M - 5) years
• Age of son = (N - 5) years

As per given condition,

→ 1/7(M - 5) = (N - 5)

→ M - 5 = 7(N - 5)

→ M - 5 = 7N - 35

→ M - 7N = - 35 + 5

→ (30 + N) - 7N = - 30 [From (1)]

→ 30 - 6N = - 30

→ - 6N = - (30 + 30)

Negative sign cancel throughout

→ 6N = 60

→ N = 60/6

→ N = 10

•°• Present age of son is 10 years.

Substitute value of N in M

→ M = 30 + 10

→ M = 40

•°• Present age of father is 40 years