The difference between the side at a right angle in a right angled triangle is 14 cm the area of a triangle is 120 CM calculate the perimeter of the triangle
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heya,
let the base of a triangle is x
then height x-14
according to your question.
1/2(x)(x-14)=120
=)x^2-14x=240
==)x^2-14x-240
=)x^2-24x+10x-240
=)x(x-24)+10(x-24)=0
=)(x+10)(x-24)=0
=)x=24,. x=-10(kehlate this)
=)then ,other side will be
x-14=10
by using Pythagoras theorm.
heipotenous=√24^2+10^2
h=√576+100=√676
h=26
hence,the side is 24,10,26,
hope it help you
@rJukumar☺
let the base of a triangle is x
then height x-14
according to your question.
1/2(x)(x-14)=120
=)x^2-14x=240
==)x^2-14x-240
=)x^2-24x+10x-240
=)x(x-24)+10(x-24)=0
=)(x+10)(x-24)=0
=)x=24,. x=-10(kehlate this)
=)then ,other side will be
x-14=10
by using Pythagoras theorm.
heipotenous=√24^2+10^2
h=√576+100=√676
h=26
hence,the side is 24,10,26,
hope it help you
@rJukumar☺
pushpasingh6777:
Thanks u r the best
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