Question

the difference between the sides containing a right angle in right angle triangle is 14cm .the area of triangle is 120sqcm.find perimeter

Answer 1

let one side at right angle be x 
                    the other must be x-14
area of triangle =1/2*b*h
                  120=1/2*x*(x-14)
                    120=(x^2-14x)/2
                   240=x^2-14x
x^2-14x-240=0
x^2-24x+10x-240+0
x(x-24)+10(x-24)=0
(x-24) (x+10)=0
x-24=0
x=24

x+10=0
x=-10
x-14=24-14=10cm

(24)^2+(10)^2=a^2
576+100=a^2
679=a^2
a=26cm

hypotenuse=26cm\


perimeter of a triangle=(sum of all the sides)
                                   =(24+10+26)
                                   =60cm 

Answer 2

ans is 60 .....................