The difference between the sides of the right angled triangle is 14 cm.THe area of the triangle is 120cm square.find the perimeter of the triangle
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When the area is 120 cm And the formula for area is 1/2 x base x height.
So when we do half of 120 we get 60.
The only numbers where the differences is 14 of the sides in the triangle are 5 and 12.
Even their difference is seven and their product is 60.
So we have sides 5 and 12.
Now we need the length of the other side (the remaining one).
To find that length we have to find the hypotenuse whose formula is Square of a side + Square of b side = Square of c side
= Square of 5+ square of 12 =the remaining side
= 25+144=169( Square of 13)
The length of the remaining side is 13.
Perimeter of triangle= sum of all sides
= 5 +12+13
= 30
So when we do half of 120 we get 60.
The only numbers where the differences is 14 of the sides in the triangle are 5 and 12.
Even their difference is seven and their product is 60.
So we have sides 5 and 12.
Now we need the length of the other side (the remaining one).
To find that length we have to find the hypotenuse whose formula is Square of a side + Square of b side = Square of c side
= Square of 5+ square of 12 =the remaining side
= 25+144=169( Square of 13)
The length of the remaining side is 13.
Perimeter of triangle= sum of all sides
= 5 +12+13
= 30
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