Math, asked by gayathrijohns03, 11 months ago

The difference between the simple and compound interest on Rs 12500 for 3 years at 4% is

Answers

Answered by varaddk18

Answer:

answer is 60

Step-by-step explanation:

Compound interest short trick - P * R/100 = 12500* 12.48/100 =12.48*125=1560

simple interest P*R*N/100= 12500*4*3/100=125*4*3=1500

therefore, C.I -S.I = 1560-1500 = 60

gayathrijohns03: Sorry...Wasn't clear from where 12.48 came from?

gayathrijohns03: Can You please make it clear?

varaddk18: think by C I

varaddk18: first year 12500* 4/100= 1500 second year 12504*4/100=500.16 third year 13004.16*4/100=520.1664

Answered by gadakhsanket

Dear Student,

₹ 61

Simple interest over 3 years is -

SI = P × r × t

SI = 12500 × 4/100 × 3

SI = ₹ 1500

Compound interest over 3 years is -

CI = P [(1 + r)^t - 1]

CI = 12500 [(1 + 4/100)^3 - 1]

CI = 12500 [1.04^3 - 1]

CI = 125000 (1.1249 - 1)

CI = 125000 × 0.1249

CI = ₹ 1561

Hence, difference between the simple and compound interest is 1561-1500 = 61 ₹.

Thanks dear. Hope this helps you...

Previous Question

Next Question