Question

the difference between the square of two consecutive integers is 47 find the number

Answer 1

since the numbers are consecutive si let them be x&x+1
now
x*2-(x+1)*2=47
x*2-x*2-1-2x=47
-2x=48
x=-24
so other no -27+1=-23

Answer 2

let the consecutive intergers be x and x+1
A/Q
(x+1)²-x² =47

x²+2x+1 - x² =47

2x=47-1

x=46÷2
x= 23
so x+1= 23+1=24