Question

the difference between the square of two consecutive no.s is 141. Find the no.s

Answer 1

let the two numbers be a and a+1
now
(a+1)²-a²=141
2a=140
a=70
70,71 are the required numbers

Answer 2

X=70
Now, you may be asking how?
According to the question,
${(x + 1)}^{2} - {x}^{2} = 141$
${(x + 1)}^{2} = {x}^{2} + 2x + 1$
So,
${x}^{2} + 2x + 1 - {x}^{2} = 2x + 1$
$2x + 1 = 141$
$2x = 141 - 1 = 140$
$x = \frac{143}{2} = 70$

The first number = 70
Second number = 71

I hope this helps.
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