the difference between the square of two consecutive numbers ii 49 .find the numbers.
Answers
Answered by
1
Hey!!!
____________
let the two consecutive numbers be x and x + 1.
Then ATQ,
=> (x + 1)² - x² = 49
=> x² + 1 + 2x - x² = 49
=> 2x = 48
=> x = 24
Thus the numbers are 24 and 25
______________
Hope this helps✌️✌️
____________
let the two consecutive numbers be x and x + 1.
Then ATQ,
=> (x + 1)² - x² = 49
=> x² + 1 + 2x - x² = 49
=> 2x = 48
=> x = 24
Thus the numbers are 24 and 25
______________
Hope this helps✌️✌️
abhay022:
Brother 24 and 25 is the correct answer .. (a+b)(a-b) = (a^2 -b^2).. ........ (25^2 - 24^2 ) = (25-24)(25+24) .... = (49)(1) = 49
oh yes
..
ok
Answered by
1
Hey !
Here is your answer !!!
___________________
❇Let the numbers be x and x + 1 ✔
❇ According to the question
❇ ( x + 1 )2 - ( x )2 = 49
❇ x2 + 1 + 2x - x2 = 49
❇ 1 + 2x = 49
❇ 2x = 48
❇ x = 24 ✔
Hence the numbers are 24 and the other number is 25✔
______________
❇Hope this will help you !!✔
❇❇Have a great day !✔✔
@Ujjawal
Here is your answer !!!
___________________
❇Let the numbers be x and x + 1 ✔
❇ According to the question
❇ ( x + 1 )2 - ( x )2 = 49
❇ x2 + 1 + 2x - x2 = 49
❇ 1 + 2x = 49
❇ 2x = 48
❇ x = 24 ✔
Hence the numbers are 24 and the other number is 25✔
______________
❇Hope this will help you !!✔
❇❇Have a great day !✔✔
@Ujjawal
Similar questions