the difference between the squares of two consecutive numbers is 141 .Find the numbers
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Answered by
43
let one number be x. Thus it's successor will be x+1.
(x+1)^2 - x^2=141
x^2+2x+1-x^2 = 141
2x = 141 - 1
2x = 140
x = 70
Thus the two numbers are 70 & 71 (i.e x+1).
(x+1)^2 - x^2=141
x^2+2x+1-x^2 = 141
2x = 141 - 1
2x = 140
x = 70
Thus the two numbers are 70 & 71 (i.e x+1).
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