the difference between the squares of two consecutive integers is 47 find the numbers
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x^2+(x+1)^2=47
x^2+x^2+2x+1=47
2x^2+2x-46=0
x^2+x-23=0
solve the equation and you will get the answer
x^2+x^2+2x+1=47
2x^2+2x-46=0
x^2+x-23=0
solve the equation and you will get the answer
mohan66:
I can't understand pls tell again
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