The difference between the squares of two consecutive numbers is 31. Find the number
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Let the consecutive numbers be n,n+1
Given difference between their squares is 31
⟹(n+1)2−n2=31
⟹2n+1=31⟹n=15
The consecutive numbers are 15,16
Answered by
1
Answer:
15,16
Step-by-step explanation:
Let the consecutive numbers be n,n+1
Given difference between their squares is 31
⟹(n+1)
2
−n
2
=31
⟹2n+1=31⟹n=15
The consecutive numbers are 15,16
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